A stationary body of mass m explodes into three parts having masses in the ratio 13 3. A body of mass m at rest gets exploded .

A stationary body of mass m explodes into three parts having masses in the ratio 13 3 View Solution. (D) 2. One part retraces its path, the second one comes to rest. 5k points) A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. A particle of mass 4 m which is at rest explodes into three fragments. A stationary body of mass 3 kg explodes into three equal pieces. The velocity of the heaviest fragment will be A body of mass 4m at rest explodes into three pieces. Explanation: From the law of conservation of momentum `3 xx 16 = 6 xx "v"` `therefore "v" = 8 "m/s"` `therefore "K. Two parts fly off at night angles to each other with velocities of 9 m/s and 12 m/s. What is the stretch of length you can see on the wall? Group of answer choices 1 0. Verified by Toppr . Initially M A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1: 1: 3. C. The minimum energy released in the process of explosion is . The two fragments with equal mass move at right angles to each other with velocity of 15 m s−1. Find the statement(s) that is/are true for this case assuming that the energy of the blast is totally To solve the problem, we need to apply the principle of conservation of momentum. A stationary body of mass m explodes into 3 parts of masses m in the ratio 1 : 3 : 3, its two fractions having equal masses moving at right angles to each other with a velocity of 15 m s − 1. If the explosion takes place in 10 − 3 s, find out the average force exerted on the third piece. Find the maximum and minimum distances between the bars during the subsequent motion of the system, if the masses of the bars are: (a) equal; (b) equal to A stationary body explodes into two fragments of masses `m_(1)` and `m_(2)`. Two of the pieces fly off at right angles to each other, one with a velocity \(2 \hat{i} A 1 kg stationary bomb is exploded in three parts having mass 1 : 1 : 3 respectively. A stationary body explodes into two fragments of masses m 1 and m 2. The magnitude of resultant momentum of two fragments each of mass I kg moving with velocity 21 m/s in perpendicular directions isAccording to law of conservation of linear momentum Click here👆to get an answer to your question ️ (4) 40 m/s (129) A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1:1: 3. Step 3: Calculate the ratio of velocities Click here:point_up_2:to get an answer to your question :writing_hand:a stationary bomb explodes into two parts of masses 3 kg and 1 kg the A shell of mass 20 kg at rest explodes into twofragments whose masses are in the ratio 2:3. LEVEL-1 de Broglie Hypothesis : 29. The velocity of the heavier part in m/s is A bomb explodes into three fragments having masses in the ratio of 1: 1: 3. CALCULATION: A shell of mass m is at rest initially and it explodes into three fragments having mass in the ratio 2 ∶ 2 ∶ 1 as shown in the figure below; Here we have the ratio of the masses as; 2: 2: 1 Mass of body m = 12 k g; The ratio of masses of smaller part A to bigger part B, m A / m B = 1 / 3; The final kinetic energy of body A, K E A = 216 J; The final velocity of body B, v B; Step 2: Formula Used: Law of conservation of momentum, Total initial momentum = Total final momentum of the system . One with a velocity of $2{\text{i}}\,{\text{m}}{{\text{s}}^{ - 1}}$ and the other with a velocity of $3{\text{j}}\,{\text{m}}{{\text{s}}^{ - 1}}$. Two of the fragments each of mass m are found to move with a speed 'v' each in mutually perpendicular directions. Momentum of sytem before explosion = momentum of system after explosion or `mv=m_(1)v_(1)+m_(2)v_(2)+m_(3)v_(3)` or A stationary object explodes into masses m 1 and m 2. 0 m / sB. 0 kg fragment travels north at 33 m / s. Again, Click here👆to get an answer to your question ️ 2. Two of the pieces move with a speed \(v\) each in mutually perpendicular direc A particle of mass 4 m which is at rest explodes into three fragments. The velocity of the third piece will be:a)15 ms-1b)25 ms-1c)35 ms-1d)50 ms-1Correct answer is option 'B'. Therefore, the mass of the third part will be \( 3m \). if the explosion occur in 0. It breaks into three equal parts. A bomb of mass 9 kg explodes into two pieces of mass 3 kg and 6 kg. Find the magnitude; An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1. A body of mass 1 kg initially at rest explodes and breaks into three fragments of masses in the ratio 1:1:3. The fragments of same mass move perpendicular to each other with speeds 30 m/s, while the heavier part remains in the initial direction. The piece with mass M/4 flies; An exploding object breaks into three fragments. To solve the problem of the stationary shell breaking into three fragments, we can follow these steps: Step 1: Understand the Initial Conditions The shell is initially stationary, which means its total momentum is zero. The two fractions with equal masses move at right angles to each other with a velocity of 1. asked Feb 2, 2023 in Solutions for A body of mass M at rest explodes into three pieces, in the ratio of masses 1 : 1 : 2. m 1 m 2. Correct option. Two smaller pieces fly off perpendicular to each other with velociti A body of mass `1kg` initially at rest explodes and breaks into three parts of masses in the ration ` 1: 2: 3. Two of the pieces fly off at right angles to each other, with velocities of 2 ^ i m/s and 3 ^ j m/s. Q. The velocity of the heaviest fragment will beA. The parts will move (a) in same direction (b) along different lines (c) in opposite directions with equal speeds A body of mass 4 m at rest explodes into three pieces. Let's break it down step by step. The So the centre of mass will not change. There is a smooth cover on the peg (so that the rope passes through the narrow channel formed between the peg and the cover) to prevent Solution For A stationary body of mass m explodes into 3 parts with mass ratio of 1:3:3. 1800J C. 13 √2 ms 1C. M will explode in M/2 and M/2 masses; It explodes into three fragments having mass in the ratio 2 ∶ 2 ∶ 1. If momentum of one fragment is `p`, the energy of explosion is A body of mass $1 \mathrm{~kg}$ initially at rest, explodes and breaks into three fragments of masses in the ratio $1: 1: 3$. One with a velocity of 2 ˆ i m/s and the other with a velocity of 3 ˆ j m/s. A stable body of mass $$4$$ m suddenly explodes into three parts. If momentum of one fragment is `p`, the energy of explosion is asked Jun 14, 2019 in Physics by PalakAgrawal ( 76. 0 m / sD. Example 8. The distance to the wall from the binoculars is still 28 meters. The final velocity of body A, v A = 16 m / s. 0k points) Correct option a 7√2Explanation:Since 5 kg body explodes into three fragments with masses in the ratio 1 : I : 3 thus masses of fragments will be 1 kg 1 kg and 3 kg respectively. 7k points) An object of mass $$3kg$$ at rest in space suddenly explodes into three parts of same mass. View Solution; A 5 kg stationary bomb explodes in three parts having mass 1:1:3 respectively. Its two parts having equal masses move at right angles to each other with 15 m / s − 1 each. If momentum of one fragment is p, A stationary Now you use a different pair of binoculars. The rope begins to slide under the action of gravity. The two pieces of equal mass fly off perpendicular to each other with a speed of 30 m/s each. A body of mass 1 kg at rest explodes into three fragments of masses in the ratio 1 : 1 : 3 . If the explosion occurs in $${ 10 }^{ -4 }s$$, the average force acting on third piece in newton is:- A stationary particle explodes into two particles of masses x and y which move in opposite directions with velocity v 1 and v 2 . Step 2: Identify the Masses and Velocities > After the explosion, the body splits into three pieces: - Two pieces each of mass \( A body of mass m at rest gets exploded into 3 parts, having masses in the ratio 1: 1: 3. A \[1Kg\] stationary bomb exploded in three parts having mass ratio \[1:1:3\]. The velocity of third is : A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1: 1: 3. The two pieces of equal mass fly off perpendicular to each other with a speed of 15 Two smaller pieces fly off perpendicular to each other with velocities of 30 ms -1 and 40 ms -1 respectively. 10/√2 m s 1D. Two pieces go off at right angles to each other; 1. 0001, the average force acting on the third piece in newton is, A particle of mass 4 m, which is at rest, explodes into masses m, m and 2 m. The fragments of same mass move perpendicular to each other with speeds 30 m / s, while the heavier part remains in the initial direction. Two of fragments, each of mass m are found to move with a speed v each in mutually perpendicular directions. A 4. Thus, the mass of fragments will be x, x, 2x. The total KE of the two parts after is A. The range of the projectile was 100 m if no explosion would have taken place. The two pieces of equal mass fly off perpendicular to each other with a speed of 30 m / s each. A body of mass m at rest gets exploded A body of mass \\( M \\) at rest explodes into three pieces, in the ratio of masses 1:1:2. 0001, the average force acting on the third piece in newton is, A \[1Kg\] stationary bomb exploded in three parts having mass ratio \[1:1:3\]. The masses of the parts are in the ratio 1: 1: 3. Object A of mass m, is moving at a velocity v 1 to the right. Part 2 has a mass of 700 gram and moves with a speed of 15 m/s in -X direction. One with a velocity of `2h . What is the velocity of the heavier fragment ? A stationary firework explodes into three different fragments that move in a horizontal plane, as illustrated in Fig. Therefore, the initial momentum of A stationary body of mass m explodes into the three parts having masses in the ratio 1: 3: 3. Two of the pieces fly off in two mutually perpendicular directions, one with a velocity of 3 ˆ i m s 1 and the other with a velocity Problem: Explosion (1998) 67. E of heavy fragment. The velocity of heaviest fragment in ms will be (1) 7/2 (2) 5/2 (3) 3/2 Vijayawada 0. 489 m 2 0. 5 kg, initially at rest, into three pieces, two smaller pieces of equal masses and the third having double the mass of either of the small pieces. The velocity of third is : A body of mass m at rest gets exploded into 3 parts, having masses in the ratio 1: 1: 3. The total mechanical energy released in the process of explosion is k m v 2. If the explosion takes place in 10-5 sec, the average force acting on the third piece in newton is: (A) (2 + 3) x A body mass of 1 k g initially at rest explodes and breaks into three parts. They were first disclosed by English physicist and mathematician Isaac Newton. 11. What must have been the speed of heavier part ? Tardigrade; Question; Physics; A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1: 1: 3 . Two pieces, each of mass m move perpendicular to each other with equal speeds v. The velocity of the heavier part in m/s is Step by step video & image solution for A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. As the body explodes into three equal pieces there mass must be equal An explosion blows a rock into three pieces Two pieces whose masses are 200 kg and 100 kg go off at 90 ∘ to eachother with a velocity of 8 m / s and 12 m / s respectively If the third piece flies off with a velocity of 25 m / s then calculate the mass of this piece and indicate the direction of flight of this piece in a diagram. What is the velocity of the heavier fragment A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. A stationary body of mass \(3 kg\) explodes into three equal pieces. A stationary object explodes, breaking into three pieces of masses m, m, and 3m. 1200J D. Complex Analysis A bomb at rest explodes into 3 parts on same mass. They are labeled as having a Field of View of 2. 5 m A stationary bomb of 10kg mass explodes into 3 fragments. If two parts having equal masses fly off perpendicularly to each other with a velocity of 18 m / s, then calculate the velocilty of the third part which has a mass 3 times the mass of each part. 0 m s-1 perpendicular to line AB. the speed of the heavier fragment is A 1 kg stationary bomb is exploded in three parts having masses in ratio 1:1:3 respectively parts having same mass move in perpendicular direction with velocity 30m/s ,then the velocity of bigger part will be? A 5 kg stationary bomb is exploded in three parts having mass 1 : 1 : 3 respectively. It explodes into three fragments having masses in the ratio 2: 2: 1. A stationary body of mass m explodes into three parts having masses in the ratio 1 : 3 : 3. Parts having same mass move in perpendicular direction with velocity 30 m s – 1, then the velocity of bigger part will be : - A stationary bomb of 10 kg mass explodes into 3 fragments. Therefore, the initial momentum is zero. Step 1: Understand the Initial Conditions Initially, the body of mass \( M \) is at rest. If two parts of mass m moving with velocity v perpendicularly, then find out the velocity of the third part of mass $$2$$ m. A stationary bomb explodes into two parts of masses 3 k g and 1 k g. The fragments with equal A stationary body of mass $$3kg$$ explodes into three equal pieces. Initially, the body of mass M is at rest. Find k. Solve. The fragment of mass 3. The velocity of the 12 A stationary body explodes into two fragments of masses `m_(1)` and `m_(2)`. A body of mass `1 kg` initially at rest, explodes and breaks into three fragments of masses in the ratio `1 : 1 : 3`. If momentum of one fragment is p and one fragment of mass m 3 remains at rest, the energy of explosion is: Q. We have, K E = p 2 2 m 2 K E = p v where p is the momentum. What is the velocity of the heavier fragment A stationary body of mass 3 kg, explodes into three equal parts. The two pieces of mass m move off at right angles to each other with the same magnitude of momentum mV, The centripetal acceleration of particle of mass m moving with a velocity v in a circular orbit of radius r is. To cancel the momentum shown of the other two pieces, the 3m piece would need an x component of momentum p x = mV and a y component of momentum p y = mV giving it a total momentum of √2mV using Pythagorean theorem. Two of the pieces fly off in two mutually perpendicular directions,one with the velocity of $$\begin{matrix} 4 \hat { j } { ms }^{ -1 } \end{matrix}$$ and other with $$\begin{matrix} 3 \hat {i } { ms }^{ -1 } \end{matrix}$$. The smaller fragment moves with a velocity of6 m/s The kinetic energy of the larger fragment is96 (D)(2) 216 J(3) 144 J(4) 360 J Given, the body of mass M moving with velocity V exploded into two equal parts. The velocity of third is : To solve the problem, we will follow these steps: Step 1: Understand the initial conditions The body of mass \( 4m \) is initially at rest. 5 kg fragment travels west at 15 m / s. 5 m s − 1 Then the velocity of the third body is: Here m 1, and m 2 be the masses of the two bodies, u 1, and u 2 be the initial velocity, and v 1, and v 2 be the final velocity. The piece with mass M/4 flies; An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1. Two of the pieces fly off at right angles to each other. Uh We have a body which explodes into three parts with math ratio one is two, threes 23 The two fragments with comas move at right angles. Find the ratio of their radii. The two pieces of mass m move off at right angles to each other with the same A stationary object explodes, breaking into three pieces of masses m, m, and 3m. The velocity of mass 3 kg is 16 m/s, The kinetic energy of mass 6 kg is 192 J. Therefore, the initial momentum of the system is zero. The velocity of the third piece will be: 25 ms-1. ` If the two pieces of equal masses fly asked Jun 10, 2019 in Physics by AarohiBasu ( 85. Q4. Newton’s 1 st law states that a body at rest or uniform motion will continue to be at rest A 1 kg stationary bomb is exploded in three parts having mass ratio 1:1: 3. A stationary shell of mass *5m* explodes in to two parts and their masses are in the ratio 2:3, then the ratio of their de Broglie A body of mass \(3 \mathrm{~m}\) at rest explodes into three identical pieces. A stationary object explodes, breaking into three pieces of masses m, m, and 3m. 98 m 3 0. E" = Click here:point_up_2:to get an answer to your question :writing_hand:level1de broglie hypothesis 29a stationary shell of mass 5m explodesin to two parts and their. Two parts fly off at night angles A stationary body of mass 3kg explodes into three equal piece . 15/√2 m s 1 The bomb exploded after 10 s into two pieces of masses in the ratio 1: 5. If the third piece flies off with a velocity 40 m/s, compute the mass of third piece. The fragments with equal masses fly in mutually perpendicular directions each with speed of 21 m/s. Assuming that both particles m; A stationary bomb of 10kg mass explodes into 3 fragments. 4 MeV (D) 17. NCERT Solutions Class 12 Accountancy Part 1; NCERT Solutions Class 12 Accountancy Part 2; NCERT Solutions For Class 9 Maths Chapter 13; NCERT Solutions For An explosion blows a rock into three parts. A body of mass 1 kg initially at rest, explodes and breaks into three fragments of masses in the ratio 1: 1: 3. A 1 kg stationary bomb is exploded in three parts having mass 1 : 1 : 3 respectively. According to the principle of conservation of the linear momentum. Find the K. Then An object located at the origin and having mass M explodes into three pieces having masses M/4, M/3, and 5M/12. Step 3: Calculate the ratio of velocities of masses A and B: Click here👆to get an answer to your question ️ 19. The two pieces of equal mass fly off perpendicular to each other with a speed of 30 m / s each. A body of mass 8kg at rest explodes into Since the body explodes into three equal parts, therefore `m_(1)=m_(2)=m_(3)=m/3=1kg` Let the velocity of the third part be `vecv`. 25 m 5 1. Two fragments having masses in the ratio 1: 3 move at right angles to each other with a velocity of 15 m / s. Two bodies of different masses are dropped from heights of 16 m and 25 m A body of mass 1 kg initially at rest explodes and breaks into three fragments of masses in the ratio 1:1:3. Explanation: In the given problem A body of mass explodes at rest break up into three parts. Find the velocity of part 3. The total KE of the two parts after explosion is 2400 J A stationary body explodes into two fragments of masses `m_(1)` and `m_(2)`. Parts having same mass move in perpendicuiar directions with velocity 39 m/s, then the velocity of bigger part will be. A stationary body of mass 3 kg, explodes into three equal parts. a stationary bomb explodes into two parts of A stationary body of mass 3kg explodes into three equal piece . 96 m VIDEO ANSWER: 29 in this question. A stationary object explodes into masses m 1 and m 2. The two pieces of equal mass fly-off perpendicular to each other, with a speed of $15 \mathrm{~m} / \mathrm{s}$ each. If the explosion occurs in 104s, the average force acting on the third piece in newton is (2009) (a) (31 +4j)x10-4 (b) (31 - 49)x10+ (c A bomb explodes into three fragments having masses in the ratio of 1: 1: 3. Step 2: Define the masses Let the mass of each of the two smaller parts be \( m \). 2160J A bomb of mass 9kg explodes into two pieces of masses 3 kg and 6kg. If momentum of one fragment is `p`, the energy of explosion is asked Jun 19, 2019 in Physics by MohitKashyap ( 76. The two pieces of equal mass fly off perpendicular to each other with a speed of 15 ms − 1 each. Step 3: Calculate the Q. What is the velocity of the heavier fragment ? A 5 kg stationary bomb is exploded in three parts having mass 1: 1: 3 respectively. A. Parts having same mass move in perpendicular directions with velocity 30 m/s, then the velocity of bigger part will be :- (1) 10/2 m/s (2) Tm/s (3) 15/2 m/s Tz m/s A bomb of mass 16 kg at rest explodes into two pieces of masses 4 kg and 12 kg. The piece with mass M/4 flies; Mass A is initially moving with some unknown velocity in the +x-direction. Parts having same mass move in perpendicular directions with velocity 30 m/s , then the velocity of bigger part will be: A bomb at rests explodes into three parts of equal masses. Let the body while uploaded was at the origin of the co-ordinate system. A body of mass `1 kg` initially at rest, explodes and breaks into three fragments of masses in the ratio `1 : A body of mass explodes at rest break up into three parts. If the explosion takes place in 10 − 5 s, the average force acting on the third piece in newtons is : In the given problem a body of mass M explodes into three pieces of mass ratio 1:1:2. 5 ms -1. A body of mass `1kg` initially at rest explodes and breaks into three parts of masses in the ration ` 1: 2: 3. If the velocity of the heavier fragment is 10√(x) , determine x. Mass of another part B, m B = 6 k g. The fragments with equal masses fly in mutually perpendi asked Jan 28, 2020 in Physics by Aryangupta ( 92. The pieces scatter on a horizontal, frictionless xy-plane. 3. 2. They move in opposite directions with velocities V 1 and V 2. A body mass of 1 k g initially at rest explodes and breaks into three parts. Since the initial object was stationary and the total momentum was zero it must also have zero total momentum after. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. Find magnitude and directi; An object of mass m = 15 kg initially at rest Click here👆to get an answer to your question ️ A 1 kg stationary bomb is exploded in three parts having mass ratio 1:1:3 . The object at rest suddenly explodes into three parts with the mass ratio 2: 1: 1 NCERT Solutions for Class 10 Maths Chapter 13; A body at rest breaks into two pieces of equal masses. 0 M has a velocity of 7. 0025 m 4 3. 0 kg piece with a velocity 8 m/s. Two parts fly off at night angles An object located at the origin and having mass M explodes into three pieces having masses M/4, M/3, and 5M/12. What is the velocity of the heavier fragment ? Q. Parts having same mass move in perpendicular direction with velocity 30 m s – 1, then the velocity of bigger part will be : - One with a velocity of $2{\text{i}}\,{\text{m}}{{\text{s}}^{ - 1}}$ and the other with a velocity of $3{\text{j}}\,{\text{m}}{{\text{s}}^{ - 1}}$. The distance of the third part from the point of projection when it finally lands on the ground is - (A) 100 m (B) 150 m (C) 250 m (D) 300 m Mass of bomb m = 9 k g. The velocity of 3kg mass is `16ms^(-1)`. 23 A bomb at rest explodes into two parts of masses m 1 and m 2 An object of mass $$3kg$$ at rest in space suddenly explodes into three parts of same mass. 0k points) class-11; centre-of-mass; 0 votes. A body of mass 1 kg initially at rest explodes and breaks into three fragments of masses in the ratio 1:1. We need to calculate the average force acting on the third piece in newtons. Open in App. two of the piece fly off in perpendicular direction one with velocity 3i m/s and the other with velocityof 4j m/s . The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s . 1 kg body explodes into three fragments. Parts having same mass move in perpendicular directions with velocities 30 m/s and 30 m/s. The velocity of third is : A 5 kg stationary bomb is exploded in three parts having masses in the ratio 1 : 1: 3. A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. 0 kg piece with a velocity of 12 m/s and other 2. 7k points) Click here👆to get an answer to your question ️ A 1 kg stationary bomb is exploded in three parts having mass ratio 1:1:3 . 4 times the mass of the other. Click here👆to get an answer to your question ️ A body of mass 1 kg, initially at rest, explodes and breaks into three fragments of masses in the ratio 1:1:3 . If the explosion takes place in ${10^{ - 5}}{\text{s}}$, the average force acting on the third piece in newtons is: Tardigrade; Question; Physics; A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1: 1: 3 . Click here👆to get an answer to your question ️ 10. If the fragments having equal mass fly off along mutually perpendicular directions with speed v, the speed of the third (lighter) fragment is: A 5 kg stationary bomb explodes in three parts having mass 1:1:3 respectively. asked Jun 19, 2019 in Physics by MohitKashyap (76. Two of these parts, having mass 4 kg and 2 kg, fly apart perpendicular to each other with a velocity of 2 ms-1 and 3 ms-1. Step 2: Formula Used: Law of conservation of momentum, Total initial momentum = Total final momentum of the system . A stationary body explodes into four identical fragments such that three of them fly off mutually perpendicular to each other with the same A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. The velocity of the heaviest fragment will be Q. The two pieces mass fly off perpendicular to each other, with a speed of 3 m / s each. Parts having same mass move in perpendicular directions with velocity \[30m/s\], then the velocity of bigger part will be, An object located at the origin and having mass M explodes into three pieces having masses M/4, M/3, and 5M/12. The velocity of the heaviest fragment will be A stationary body of mass `3 kg` explodes into three equal pieces. A blast breaks a body of mass 0. 4 Mev (C) 8. The ratio of their kineticenergy is A stationary object explodes into masses m 1 and m 2. Find the statement(s) that is/are true for this case assuming that the energy of the blast is totally A stationary bomb explode into two parts of masses 3kg and 1kg. Parts having same mass move in perpendicular directions with velocity \[30m/s\], then the velocity of bigger part will be, A body mass of 1 k g initially at rest explodes and breaks into three parts. Newton’s First Law of Motion. The third part has a mass that is three times the mass of each of the other two parts. B. After the blast, the two smaller masses move at right angles to one another with equal speed. 9. If two parts having equal masses fly off perpendicularly to each other with a velocity of 18 m / s, then calculate the velocity of the third part which has a mass 3 times the mass of To solve the problem, we need to apply the principle of conservation of momentum. A 2. 89 m / sC. 5 m s − 1 Then the velocity of the third body is: A stationary body explodes into three fragments of masses m 1, m 2 and m 3. The two places of equal masses tly oft perpendicular to each other, with a speed of 30 m/s each. The speed of heavier part is: A blast breaks a body of mass 0. What is the velocity of the third body A body of mass explodes at rest break up into three parts. asked Apr 5, 2019 0 = M/4 (6 hat i) + M/4 8 hat j + M/2 vec v(3)A body oa mass M at rest explodes into three pieces, two of which of mass (M/4) each are thrown- off in perpendicular directions with velocities of 6 ms^(-1) and 8 ms^(-1) respectively. 600J B. 0 degrees. . Step 2: Analyze the explosion The body explodes into In the resulting collision a fraction r of the total energy is "lost" into heat and other forms of energy. The ratio of kinetic energy E 1 to kinetic energy E 2 is. The two pieces of equal mass fly in mutually perpendicular direc A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. Parts having same mass move in perpendicular directions with velocity 39 ms 1, and then the velocity of bigger part will beA. The total kinetic energy generated due to explosion is NCERT Solutions Class 12 Accountancy Part 1; NCERT Solutions Class 12 Accountancy Part 2; A body of mass 4 m at rest explodes into three pieces. A 5 kg stationary bomb is exploded in three parts having masses in the ratio 1 : 1: 3. 2 m 1 m 2. The velocity of the bigger part will be A body of mass m at rest gets exploded into 3 parts, having masses in the ratio 1: 1: 3. Two of the pieces fly off at right angles to each other, one with a velocity 2 m/s and the other with a velocity 3j m/s. A stationary body of mass $3kg$ explodes into three equal pieces. A body of mass 8kg at rest explodes into A body of mass 1 kg initially at rest, explodes and breaks into three fragments of masses in the ratio 1: 1: 3. Two of the fragments of masses m and 2 m are found to move with equal speed v each in opposite directions. Two of the pieces fly off at right angles to each other, one with a velocity 2 î m / s and A stationary body explodes into four identical fragments such that three of them fly off mutually perpendicular to each other with the same Kinetic energy Find the energy of the explosion A 7Eo B 6Eo C. 5 m / s A body of mass m at rest gets exploded into 3 parts, having masses in the ratio 1: 1: 3. If momentum of one fragment is p and one fragment of mass m 3 remains at rest, the energy of explosion is: View Solution A stationary particle breaks into two parts of masses \( \mathrm{m}_{A}\) and \(\mathrm{m}_{B}\) which move with : m_{A}\ v_{A}\) (4) \(1: 1\) A nuclei at rest breaks into two parts with mass ratio 1 : 2. Newton’s 1 st law states that a body at rest or uniform motion will continue to be at rest A stationary body of mass m explodes into three parts having masses in the ratio 1:3:3. No exterior forces are involved in the explosion process; instead, internal forces are what cause the explosion to happen. Two of the pieces fly off in two mutually perpendicular directions, one with a velocity of 3i ms -1 and other with a velocity of 4 jms. Two smaller pieces fly off perpendicular to each other with velocities of 30 ms-1and 40 ms-1respectively. The ratio of their masses is 1: 1: 3. The velocity of the heaviest fragment will be - A body of mass 1 kg at rest explodes into three fragments of masses in the ratio 1 : 1 : 3 . A bomb at rests explodes into three parts of equal masses. 7. 28 Two particle of mass m and 2m moving in opposite directions collide elastically with velocities v and The laws of motion, which are the keystone of classical mechanics, are three statements that defined the relationships between the forces acting on a body and its motion. 1 answer. two of these parts having mass 4kg and 2kg, fly apart perpendicular to each other with a velocity of 2m/s and 3m/s. `m_2=2kg` and `m_3=3kg` are A stationary body explodes into three fragments of masses m 1, m 2 and m 3. 7k points) A stable body of mass $$4$$ m suddenly explodes into three parts. If the initial velocity is zero, the center of mass: a) Remains stationary b) Moves in the direction of the smallest mass c) Moves in the direction of the largest mass d) Moves in the direction of the middle mass A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. What is the velocity of the | Two parts have equal mass and fly off perpendicularly to each other with a velocity of 18 m/s. The third piece will be thrown-off with a velocity of A stationary body explodes into four identical fragments such that three of them fly off mutually perpendicular to each other, each with same `KE, E_ class-11; centre-of-mass-&-momentum-conservation; 0 votes. The momentum of the two parts are $$4\hat{i}$$ and $$2\hat{j}$$. 14. m 2 m 1. Solution. Find magnitude and directi A body of mass 1 kg at rest explodes into three fragments of masses in the ratio 1 : 1 : 3 . The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m / s. The velocity of the heavier part in m/s is A body of mass 1 kg initially at rest, explodes and breaks in to three fragments masses in the ratio 1:1:3 the two pieces of equal mass fly off perpendicular to each other,with speed of 15 m/s each . Hence, M = x + x + 2x = 4x kg. The explosion takes place in ${10^{ - 5}}{\text{s}}$. A body of mass explodes at rest break up into three parts. By momentum conservation, we have: p 1 = p 2 m 1 A stationary body explodes into three fragments of masses m 1, m 2 and m 3. If momentum of one fragment is p and one fragment of mass m 3 remains at rest, the energy of explosion is: View Solution A shell of mass m is at rest initially and it explodes into three fragments having mass in the ratio 2 ∶ 2 ∶ 1 as shown in the figure below; Here we have the ratio of the masses as; 2: 2: 1 According to the conservation of momentum, there is only one mass that explodes into three different fragments, therefore the initial and final momentum is written as; A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. Oh And with velocity 15 m purse. The position vector of three particles of masses `m_1=1kg`. The speed of the heavier fragment is : A heavy rope of mass m and length 2 L is hanged on a smooth little peg with equal lengths on two sides of the peg. 3 Mev A stationary body of mass 3 kg explodes into three equal pieces. Right part of the rope is pulled a little longer and released. A nucleus of mass M at rest splits into two parts having masses \(\frac{M'}3\) and \(\frac{2M'}3\) (M' < M). 1. Part 3 has a mass of 500 gram. Problem 1 A stationary bomb explodes into three parts which move horizontally. Thus, momentum of the system will be conserved. If two parts of mass m moving with velocity v perpendicularly, then find out the velocity of the third part of mass $$2 Question From – Cengage BM Sharma MECHANICS 2 CENTRE OF MASS JEE Main, JEE Advanced, NEET, KVPY, AIIMS, CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-A stati It suddenly explodes into three pieces. Help Page 13; 9702 November 2014 Paper 11 12 Worked Solutions | A-Level Physics; Topics. If two parts having equal masses fly off perpendicularly to each other with a velocity of 18 m / s, then calculate the velocity of the third part which has a mass 3 times the mass of each part. Mass B is twice as massive as mass A and initially at rest. Two of the pieces each of mass m move with a speed v each in mutually perpendicular directions. A nucleus at rest splits into two nuclear parts having same density and radii in the ratio 1:2. 10 √2 ms 1B. 8 times the mass of the other. Then A stationary body of mass 3 kg explodes into three equal pieces. Parts having same mass move in perpendicular direction with velocity 30 m/s, then the velocity of bigger part will be (a) 10 √ 2 m/sec (b) 10/ The laws of motion, which are the keystone of classical mechanics, are three statements that defined the relationships between the forces acting on a body and its motion. Q5. A stationary nucleus breaks into two nuclei having velocities in ratio 3:2. The two pieces of mass m move off at right angles to each other with the same magnitude of A stationary body of mass 3 kg explodes into three equal pieces. Mass of one part A, m A = 3 k g. 2 m 1 m 1. D. The two pieces of equal mass fly in mutually perpendicular directions with a speed of 30 m / s each . Part 1 has a mass of 1 kg and moves in +X direction with a speed of 20 m/s. qwwbbb isyrd oqkdr ekgraf iesjq six atto yljuzsxp yftpjg lrqzjt